import numpy as np def mandelbrot(width: int, height: int, *, x: float = -0.5, y: float = 0, zoom: int = 1, max_iterations: int = 100) -> np.array: """ From https://www.learnpythonwithrune.org/numpy-compute-mandelbrot-set-by-vectorization/. """ # To make navigation easier we calculate these values x_width, y_height = 1.5, 1.5*height/width x_from, x_to = x - x_width/zoom, x + x_width/zoom y_from, y_to = y - y_height/zoom, y + y_height/zoom # Here the actual algorithm starts x = np.linspace(x_from, x_to, width).reshape((1, width)) y = np.linspace(y_from, y_to, height).reshape((height, 1)) c = x + 1j*y # Initialize z to all zero z = np.zeros(c.shape, dtype=np.complex128) # To keep track in which iteration the point diverged div_time = np.zeros(z.shape, dtype=int) # To keep track on which points did not converge so far m = np.full(c.shape, True, dtype=bool) for i in range(max_iterations): z[m] = z[m]**2 + c[m] diverged = np.greater(np.abs(z), 2, out=np.full(c.shape, False), where=m) # Find diverging div_time[diverged] = i # set the value of the diverged iteration number m[np.abs(z) > 2] = False # to remember which have diverged return div_time def julia(width: int, height: int, *, c: complex = -0.4 + 0.6j, x: float = 0, y: float = 0, zoom: int = 1, max_iterations: int = 100) -> np.array: """ From https://www.learnpythonwithrune.org/numpy-calculate-the-julia-set-with-vectorization/. """ # To make navigation easier we calculate these values x_width, y_height = 1.5, 1.5*height/width x_from, x_to = x - x_width/zoom, x + x_width/zoom y_from, y_to = y - y_height/zoom, y + y_height/zoom # Here the actual algorithm starts x = np.linspace(x_from, x_to, width).reshape((1, width)) y = np.linspace(y_from, y_to, height).reshape((height, 1)) z = x + 1j*y # Initialize z to all zero c = np.full(z.shape, c) # To keep track in which iteration the point diverged div_time = np.zeros(z.shape, dtype=int) # To keep track on which points did not converge so far m = np.full(c.shape, True, dtype=bool) for i in range(max_iterations): z[m] = z[m]**2 + c[m] m[np.abs(z) > 2] = False div_time[m] = i return div_time