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Tell users of the QuickStart Guide to select "Maven" on the Spring Initializr [1] (#6469)

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It looks like the default "Project" on [1] is now "Gradle - Groovy" (it used to be Maven),
but there is no Devfile usable with a SpringBoot Gradle project.

Without this, "odo init" prompts to select the "java-openliberty-gradle" Devfile,
which won't work because it executes tasks specific to OpenLiberty.

And even if we manually select the "java-springboot" Devfile,
it won't work out of the box because it requires Maven and there is
no "pom.xml" in the project generated by the Spring Initializr.

[1] https://start.spring.io/
This commit is contained in:
Armel Soro
2023-01-05 17:27:50 +01:00
committed by GitHub
parent 957ec19525
commit 9e3d554d0a
1 changed files with 6 additions and 5 deletions
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11
docs/website/docs/user-guides/quickstart/java.md
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@@ -12,14 +12,15 @@ import InitialSourceCodeInfo from './docs-mdx/initial_source_code_description.md
For Java, we will use the [Spring Initializr](https://start.spring.io/) to generate the example source code:
1. Navigate to [start.spring.io](https://start.spring.io/)
2. Under **Spring Boot** select **2.7.\*** version.
2. Select **Maven** under **Project**
3. Under **Spring Boot** select **2.7.\*** version.
:::caution
For now, don't use SpringBoot 3. Currently there is no Devfile in [registry.devfile.io](https://registry.devfile.io/) with Java 17.
:::
3. Select **11** under **Java**
4. Click on "Add" under "Dependencies"
5. Select "Spring Web"
6. Click "Generate" to generate and download the source code
4. Select **11** under **Java**
5. Click on "Add" under "Dependencies"
6. Select "Spring Web"
7. Click "Generate" to generate and download the source code
Finally, open a terminal and navigate to the directory.